Introduction:
The turning or twisting force about an axis is called torque. Consider a wheel of radius R meters acted upon by a circumferential force F Newton’s .Basically the torque is developed in the armature and hence, gross torque produced is denoted as Ta. The mechanical power developed in the armature is transmitted to the load through the shaft of the motor.
The wheel is rotating at a speed of N r.p.m
Then angular speed of the wheel is,
So, work done in one revolution is,
W = F * distance travelled in one revolution
= F * 2π R Joules
P = Power developed = Work done/ Time
P = T *ω Watts
T = Torque in N - m
ω = Angular speed in rad / sec.
let Ta be the gross torque developed by the armature of the motor in examples of torque. It is also called armature torque. The gross mechanical power developed in the armature is Eb Ia, as seen from the power equation. So if speed of the motor is N r.p.m. then,
Power in armature = Armature torque * ω
But Eb in a motor is given by,
This is the examples torque equation of a d.c motor.
A 4 pole d.c motor takes a 50 A armature current. The armature has lap connected 480 conductors. The flux per pole is 20 mWb. Calculate the gross torque developed by the armature of the motor.
Solution:
The turning or twisting force about an axis is called torque. Consider a wheel of radius R meters acted upon by a circumferential force F Newton’s .Basically the torque is developed in the armature and hence, gross torque produced is denoted as Ta. The mechanical power developed in the armature is transmitted to the load through the shaft of the motor.
Torque Equation of a D.C Motor
Let us see about examples of torque,The wheel is rotating at a speed of N r.p.m
Then angular speed of the wheel is,
So, work done in one revolution is,
W = F * distance travelled in one revolution
= F * 2π R Joules
P = Power developed = Work done/ Time
P = T *ω Watts
T = Torque in N - m
ω = Angular speed in rad / sec.
let Ta be the gross torque developed by the armature of the motor in examples of torque. It is also called armature torque. The gross mechanical power developed in the armature is Eb Ia, as seen from the power equation. So if speed of the motor is N r.p.m. then,
Power in armature = Armature torque * ω
But Eb in a motor is given by,
This is the examples torque equation of a d.c motor.
Example of torque
Let us see about examples of torque,A 4 pole d.c motor takes a 50 A armature current. The armature has lap connected 480 conductors. The flux per pole is 20 mWb. Calculate the gross torque developed by the armature of the motor.
Solution:
from where 2π r came?
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Both are really good,
Cheers,
Venkat